Book
Linear Algebra
Author
Gilbert Strang
Edition
a1=matrix([[0,0,0,1],[0,0,2,0],[0,3,0,0],[4,0,0,0]])
print a1
a1.inverse()
a2=matrix([[1,0,0,0],[-1/2,1,0,0],[0,-2/3,1,0],[0,0,-3/4,1]])
print a2
a2.inverse()
var('a,b,c,d')
A3=matrix([[a,b,0,0],[c,d,0,0],[0,0,a,c],[0,0,b,d]])
print A3
A3.inverse()
Solution by:
Tejaswi,Jyothi :prakasam engg college