#Kreyszig 309 Problemset6.1 problem 6
A = matrix(QQ,[[2,1],[1,7]])
B= matrix(QQ,[[-2,5],[0,8]])
C= matrix(QQ,[[6,0,3],[1,0,-5]])
D= matrix(QQ, [[4,0,-4],[-3,4,9]])
#A+0*C
print "Undefined since order of A is not equal to order of C"
#C-0*A
print "Undefined since order of A is not equal to order of C"
print 0*B

SageDays/Kreyszig-6.1-6 (last edited 2010-08-12 04:49:49 by Astrid)