#Kreyszig 309 Problemset6.1 problem 3
A = matrix(QQ,[[2,1],[1,7]])
B= matrix(QQ,[[-2,5],[0,8]])
C= matrix(QQ,[[6,0,3],[1,0,-5]])
#A+C
print "Undefined since order of A is not equal to order of C"
print transpose(transpose(C))
#C+transpose(C)
print "Undefined since order of A is not equal to order of C^t"

SageDays/Kreyszig-6.1-3 (last edited 2010-08-12 04:43:15 by Astrid)