#Prob 19 - solving a 2nd order DE with boundary conditions
x=var('x')
y=function('y',x)
de=diff(y,x,2)+4*y==0
desolve(de,y,ics=[0,3,-3])

SageDays/Kreyszig-2.3-19 (last edited 2010-08-09 14:03:31 by AniketBasu)