Book
Advanced Engineering Mathematics
Author
Erwin Kreyszig
Edition
8th Edition
# radius = R #volume pi = 3.1415 V = (4/3)*pi*R^3; V #area A = 4*pi*R^2 #by hypothesis #d(V)/dt = -k*A (where k is the proportionality constant) # d(R)/dt = -k # integrating this leads to, k = -0.5 cm/month #---------- # Delta(R) = 2cm - 1mm = 1.9 cm # Delta(R)/Delta(T) = -(-0.5) Delta(T) = 1.9/0.5 print Delta(T)
Solution by:
- gnash, developer, space
- bhanukiran, student, technical university of Delft
- saransh, student, sobhit university