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| A=identity_matrix(3)*(-1) A.determinant() (A/2).determinant() (-A).determinant() (A**2).determinant() A.inverse().determinant() |
print " let us take a 3x3 matrix having det= -1 as" A = matrix([[0,1,0],[1,0,0],[0,0,1]]) print A print "" print "determinant of A =", x = det(A) print x x = det(0.5*A) print "determinant of 0.5*A =", print x x = det(-A) print "determinant of -A =", print x x = det(A*A) print "determinant of A*A =", print x x = det(A.inverse()) print "determinant of A^-1 =", print x |
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| * Vignesh Ganapathiraman, Student, CMI * Pooja Kalra, Student, Malwa Institute of Technology * T R Shyam Sundar, Student, CMI * Sonam Kumar, Student, CMI |
* Ch.Sandeep, student, GITAM University * V.Vishnu Sarma, student, GITAM University |
Book
Linear Algebra
Author
Gilbert Strang
Edition
print " let us take a 3x3 matrix having det= -1 as" A = matrix([[0,1,0],[1,0,0],[0,0,1]]) print A print "" print "determinant of A =", x = det(A) print x x = det(0.5*A) print "determinant of 0.5*A =", print x x = det(-A) print "determinant of -A =", print x x = det(A*A) print "determinant of A*A =", print x x = det(A.inverse()) print "determinant of A^-1 =", print x
Solution by:
- Ch.Sandeep, student, GITAM University
- V.Vishnu Sarma, student, GITAM University
