Book
Advanced Engineering Mathematics
Author
Erwin Kreyszig
Edition
8th Edition
theta=var('theta')
A=matrix([[1,0,0],[0,cos(theta),sin(theta)],[0,-sin(theta),cos(theta)]])
Ain = A.inverse()
y1, y2,y3 = var('y1,y2,y3')
y = matrix([[y1],[y2],[y3]])
Ain*y
Solution by:
- ganesh, developer, space bhanukiran, student, technical university of Delft