Book
Advanced Engineering Mathematics
Author
Erwin Kreyszig
Edition
8th Edition
theta=var('theta') A=matrix([[1,0,0],[0,cos(theta),sin(theta)],[0,-sin(theta),cos(theta)]]) Ain = A.inverse() y1, y2,y3 = var('y1,y2,y3') y = matrix([[y1],[y2],[y3]]) Ain*y
Solution by:
- ganesh, developer, space bhanukiran, student, technical university of Delft