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⇤ ← Revision 1 as of 2010-08-09 14:14:02
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← Revision 2 as of 2010-08-12 07:16:29 ⇥
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| W=det(matrix([[1,exp(x)],[0,exp(x)]])) print W W.simplify_rational() }}} |
w=var('w') W=det(matrix([[exp(-x)*cos(w*x),exp(-x)*sin(w*x)],[exp(-x)*(-w*sin(w*x)-cos(w*x)),exp(-x)*(w*cos(w*x)-sin(w*x))]])) show(W.simplify_rational()) #W!=0, so the basis functions are linearly independent}}} |
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| * sawankumar, teaching, MGM- jnec | * dilip, teaching, rgit |
Book
Advanced Engineering Mathematics
Author
Erwin Kreyszig
Edition
8th Edition
x=var('x')
w=var('w')
W=det(matrix([[exp(-x)*cos(w*x),exp(-x)*sin(w*x)],[exp(-x)*(-w*sin(w*x)-cos(w*x)),exp(-x)*(w*cos(w*x)-sin(w*x))]]))
show(W.simplify_rational())
#W!=0, so the basis functions are linearly independent
Solution by:
- namdev, teaching, RGIT
- dilip, teaching, rgit