#Prob 13 - finding a solution to a 2nd order DE with initial conditions
x=var('x')
y=function('y',x)
de=9*diff(y,x,2)+6*diff(y,x)+y==0
desolve(de,y,ics=[0,4,-13/3])

SageDays/Kreyszig-2.3-13 (last edited 2010-08-09 14:04:28 by AniketBasu)