Differences between revisions 2 and 3
⇤ ← Revision 2 as of 2010-08-09 14:31:03 →
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Editor: lokeshpimpale
Comment:
← Revision 3 as of 2010-08-10 12:30:28 → ⇥
Size: 561
Editor: hardikgajera
Comment:
Deletions are marked like this. Additions are marked like this.
Line 19: Line 19:
print I.subs(k1=30, k2=-10) print I.subs(k1 = (-250/109), k2 = 2)

  • Book

    Advanced Engineering Mathematics

    Author

    Erwin Kreyszig

    Edition

    8th Edition 

t=var('t')
I=function('I',t)
DE = 0.5*diff(diff(I,t),t) + 40*diff(I,t) + 750*I + 25*100*sin(100*t)
I(t)=desolve (DE,[I,t])
I(0)==0
de(t)=diff(I,t)
de(0)==0
k1,k2=var('k1,k2')
solve([I(0)==0,
       de(0)==0],k1,k2)

print I.subs(k1 = (-250/109), k2 = 2)

  • Solution by: Lokesh Pimpale,student, IISER Pune

    • Hardik Gajera,student , IISER Pune

SageDays/Kreyszig-2.12-7 (last edited 2010-08-10 13:02:24 by hardikgajera)