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   * ujwala, lecturer, aurangabad

  • Book

    Advanced Engineering Mathematics

    Author

    Erwin Kreyszig

    Edition

    8th Edition 

# radius = R
#volume 
pi = 3.1415

V = (4/3)*pi*R^3; V

#area 
A = 4*pi*R^2


#by hypothesis

#d(V)/dt = -k*A  (where k is the proportionality constant)

# d(R)/dt = -k 

# integrating this leads to, k = -0.5 cm/month

#----------

# Delta(R) = 2cm - 1mm = 1.9 cm
# Delta(R)/Delta(T) = -(-0.5)

Delta(T) = 1.9/0.5 

print Delta(T)

  • Solution by:

    • gnash, developer, space
    • bhanukiran, student, technical university of Delft
    • saransh, student, sobhit university

SageDays/Kreyszig-1.4-16 (last edited 2010-08-11 11:18:41 by bhanukiran)