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Editor: Shubham
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← Revision 4 as of 2010-12-18 12:47:38 → ⇥
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Editor: Shubham
Comment:
Deletions are marked like this. Additions are marked like this.
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 G(x) = G(x)+an1*cos(n*pi/pi*x) + bn1*sin(n*pi/pi*x)
 P(x) = P(x)+an2*cos(n*pi/pi*x) + bn2*sin(n*pi/pi*x)		  G(x) = G(x)+an1*cos(n*pi/1*x) + bn1*sin(n*pi/1*x)
 P(x) = P(x)+an2*cos(n*pi/1*x) + bn2*sin(n*pi/1*x)

  • Book

    Advanced Engineering Mathematics

    Author

    Erwin Kreyszig

    Edition

    8th Edition 

var('k')
g(x) = -k
p(x) = k
a0 = integrate(g(x)/1 , (x,-1,0))
p0 = integrate(p(x)/1 , (x,0,1))
G(x)=a0
P(x)=p0
for n in range(1,8):
        
        an1 = integrate(g(x)*cos(n*x)/1, (x,-1,0))
        bn1 = integrate(g(x)*sin(n*x)/1, (x,-1,0))
        an2 = integrate(p(x)*cos(n*x)/1, (x,0,1))
        bn2 = integrate(p(x)*sin(n*x)/1, (x,0,1))       
        G(x) = G(x)+an1*cos(n*pi/1*x) + bn1*sin(n*pi/1*x)
        P(x) = P(x)+an2*cos(n*pi/1*x) + bn2*sin(n*pi/1*x)
print G(x)+P(x)

  • Solution by:

    • SHUBHAM MITTAL, STUDENT, IIT ROORKEE
    • AMIT TEWARI, STUDENT, IIT ROORKEE
    • RACHIT JHA, STUDENT, IIT ROORKEE
    • ARNAB BASU, STUDENT, IIT ROORKEE

Kreyszig-10Review-18-U (last edited 2010-12-18 12:47:38 by Shubham)