Strang-2.6_38-U

Revision 1 as of 2010-12-18 06:41:52

code_begins

h=matrix([[1,1,1,1],[1,-1,1,-1],[1,1,-1,-1]])
h.inverse()

code_ends

Solution by:
- VVL Amruthavalli,student,prakasam Engg college
- G.haritha,student,prakasam Engg college
- G.Mamatha ,student,prakasam Engg college