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Editor: 10
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A = matrix([[-1,-1,0,0,-1,0],[1,0,-1,-1,0,0],[0,1,1,0,0,-1],[0,0,0,1,1,1]])
print A		 B= matrix([[-1,-1,0,0,-1,0],[1,0,-1,-1,0,0],[0,1,1,0,0,-1],[0,0,0,1,1,1]])
print B
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   * Arnab Basu, Student, IIT Roorkee
   * Amit Tewari, Student, IIT Roorkee
   * Rachit Jha, Student, IIT Roorkee
   * Shubham Mittal, Student, IIT Roorkee		  *<yedukondalu>, <student>, <Prakasam engineering College>
   *<n srija> <student>, <Prakasam engineering College>
   *<triveni>, <student>, <Prakasam engineering College>
  
   *<siva latha>, <student>, <Prakasam engineering College>

  • Book

    Linear Algebra

    Author

    Gilbert Strang

    Edition

    		 

#To find the incidence matrix and its null-space
print 'The incidence matrix is'
B= matrix([[-1,-1,0,0,-1,0],[1,0,-1,-1,0,0],[0,1,1,0,0,-1],[0,0,0,1,1,1]])
print B
b = A.transpose()
print 'Transpose of the matrix is '
print b

  • Solution by:

  • <yedukondalu>, <student>, <Prakasam engineering College>

    • <n srija> <student>, <Prakasam engineering College>

    • <triveni>, <student>, <Prakasam engineering College>

    • <siva latha>, <student>, <Prakasam engineering College>

Strang-2.5-4-U (last edited 2010-12-18 12:12:16 by 10)