⇤ ← Revision 1 as of 2010-12-17 09:17:24
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← Revision 2 as of 2010-12-17 12:10:39 ⇥
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B=array([[0,0,1],[0,0,1],[1,1,1]]) det=B[1][1]*B[2][2]-B[2][1]*B[1][2] det det==0# det of 2x2 submatrix is non zero. thus rank is 2 # null space is empty set |
a=matrix([[0,0,1],[0,0,1],[1,1,1]]) b=matrix([[0,0,1,2],[0,0,1,2],[1,1,1,0]]) a.rank() b.rank() a.nullity() b.nullity() |
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c=array([[0,0,1,2],[0,0,1,2],[1,1,1,0]]) c[0]=c[1]-c[0] c len(c.nonzero()) #rank is number of non zero rows |
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* vsowjanya,faculty, cvr college of engineering * gharitha,student,prakasam engineering college |
* g.mamatha,student,prakasam engg college * VVL Amruthavalli,student,prakasam engineering college |
Book
Linear Algebra
Author
Gilbert Strang
Edition
a=matrix([[0,0,1],[0,0,1],[1,1,1]]) b=matrix([[0,0,1,2],[0,0,1,2],[1,1,1,0]]) a.rank() b.rank() a.nullity() b.nullity()
Solution by:
- g.mamatha,student,prakasam engg college
- VVL Amruthavalli,student,prakasam engineering college