Strang-1.6_14-U

Revision 1 as of 2010-12-17 11:48:16

code_begins

a=matrix([[1,0,0,0],[1/4,1,0,0],[1/3,1/3,1,0],[1/2,1/2,1/2,1]])
print a
a.inverse()

code_ends

Solution by:
- <sarada>, <student>, <prakasam>
- <ananthalakshmi>, <student>, <prakasam>