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⇤ ← Revision 1 as of 2010-12-18 10:40:29
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| A=matrix([[1,0,0],[2,1,3],[0,0,1]]) print A.inverse() A=matrix([[1,1,1],[1,2,2],[1,2,3]]) print A.inverse() |
a=matrix([[1,0,0],[2,1,3],[0,0,1]]) print a.inverse() a=matrix([[1,1,1],[1,2,2],[1,2,3]]) print a.inverse() |
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| * PratyushaKarnati, student,svecw | *<yedukondalu>, <student>, <Prakasam engineering College> *<n srija> <student>, <Prakasam engineering College> *<triveni>, <student>, <Prakasam engineering College> *<siva latha>, <student>, <Prakasam engineering College> |
Book
Linear Algebra
Author
Gilbert Strang
Edition
a=matrix([[1,0,0],[2,1,3],[0,0,1]]) print a.inverse() a=matrix([[1,1,1],[1,2,2],[1,2,3]]) print a.inverse()
Solution by:
<yedukondalu>, <student>, <Prakasam engineering College>
<n srija> <student>, <Prakasam engineering College>
<triveni>, <student>, <Prakasam engineering College>
<siva latha>, <student>, <Prakasam engineering College>
