Book
Linear Algebra
Author
Gilbert Strang
Edition
var('a') A = matrix ([[a,3],[4,6]]) A.add_multiple_of_row(1,0,-4/a) B=matrix([[-3],[6]]) X=A.solve_right(B) print 'soln is ::', X print 'for the system to break down permanently-' a=A[0][1]*A[1][0]/A[1][1] print 'a=',a print 'for non permanent breakdown a != 2'
Solution by:
- Amit Tewari, Student, IIT Roorkee
- Rachit Jha, Student, IIT Roorkee
- Arnab Basu, Student, IIT Roorkee
- Shubham Mittal, Student, IIT Roorkee