Differences between revisions 1 and 2
⇤ ← Revision 1 as of 2010-08-10 11:45:33 →
Size: 512
Editor: bhanukiran
Comment:
← Revision 2 as of 2010-08-10 13:09:00 → ⇥
Size: 529
Editor: bhanukiran
Comment:
Deletions are marked like this. Additions are marked like this.
Line 8: Line 8:
{{{id=1| #given

a = 1.5 #m/s^2
s = 2000
v = var('v')
Line 11: Line 15:
a = 1.5 #m/s^2 # final velocity is found using
v = sqrt(u^2 + 2*a*s )
print v
Line 13: Line 19:
s = 2000 #m    78.1024967590665
Line 15: Line 22:
v = sqrt(u^2 + 2*a*s)
Line 17: Line 23:
print v
///
78.1024967590665
}}}

{{{id=2|

///
}}}

  • Book

    Advanced Engineering Mathematics

    Author

    Erwin Kreyszig

    Edition

    8th Edition 

#given 

a = 1.5 #m/s^2
s = 2000
v = var('v')
u = 10 #m/s

# final velocity is found using
v = sqrt(u^2 +  2*a*s )
print v

        
78.1024967590665

  • Solution by:

    • gnash, developer, space
    • bhanukiran, student, technical university of Delft
    • saransh, student, sobhit university
    • ujwala, lecturer, aurangabad

SageDays/Kreyszig-1.4-3 (last edited 2010-08-10 13:09:00 by bhanukiran)