• Book	Advanced Engineering Mathematics
  Author	Erwin Kreyszig
  Edition	8th Edition

code_begins

A=matrix([[2,10**-5,10**-5],[10**-5,2,10**-5],[10**-5,10**-5,4]])
print A
T=matrix([[1,0,0],[0,1,0],[0,0,10**5]])
print T
Tin=T.inverse()
print Tin
B=Tin*A*T

code_ends

• Solution by:

  • <K.Kavitha>, <Student>, <SNIST>

  • <B.Lavanya>, <Student>, <SNIST>